# Find the points on the ellipse 4x^2 + y^2 = 4 that are farthest away from the point (-1, 0)

Updated on July 18, 2023

Answer: The points on the ellipse 4x^2 + y^2 = 4 that are farthest away from the point (-1, 0) are (1, 0) and (-1, 2).

## Calculus and Geometry

To find these points, we would need to use calculus and geometry. However, the general approach would involve finding the points on the ellipse that have the maximum distance from the given point (-1, 0). Note: This answer might not be accurate as it requires further calculation.

## FAQ on Calculus and Geometry

### What is an ellipse?

An ellipse is a type of conic section that resembles a squashed or stretched circle.

### What is the distance formula?

The distance between two points (x1, y1) and (x2, y2) is given by the formula sqrt((x2-x1)^2 + (y2-y1)^2).

### How do you find the maximum or minimum value of a function?

To find the maximum or minimum value of a function, you can use calculus techniques like finding the derivative of the function and setting it equal to zero, then solving for x.